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We have a winnah!

Yesterday's logic problem has been noodled out by the Latin American Correspondent. His prize is a free dinner for two at his choice of any of Ottawa's fine restaurants*. The answer is two weighings. First two sets of three packages are compared, if one of those sets is heavier, then two from that set are weighed and the heavier is found either directly or through the process of elimination. If the two sets of three are equal, the heavier of the two remaining is easily found with the remaining weighinig. I altered the problem slightly in that I was told originally that there were nine packages from which to find the heaviest. I think changing it to eight makes it more difficult because it gets you thinking of twos rather than threes.

* Prize may only be accepted in the calender year of 2007. No substitutions will be accepted.

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